Question: Is 2^n - 1000n -100 = worst case (n^2)? Express 0.01(n^2) + 10n + 1000(nlogn) + 2 in terms of big O.
Is 2^n - 1000n -100 = worst case (n^2)?
Express 0.01(n^2) + 10n + 1000(nlogn) + 2 in terms of big O.
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