Is $6m(2m+14)$ divisible by $4?$ Assume the variable $m$ represents an integer.

Yes, because $6$ and $4$ have a common factor of $2.$

Yes, because $6m(2m+14)$ is a divisor of $4.$

Yes, because $6m(2m+14)=4m(3(m+7))$ which is an integer because sums and products of integers are integers.

No$,$ because $6m(2m+14)=4m(3(m+7))$ which may not be an integer because sums and products of integers are not always integers.

No$,$ because $4$ is not a divisor of $6.$

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