Question: is my solution correct? If not, How do I solve it? 4. (242=4 marks/ Let f () = isin (2). J' = in() + *

is my solution correct? If not, How do I solve it?

4. (242=4 marks/ Let f () = isin (2). J' = in() + * cos (x) Suppose also that h and & are defined as follow: h'(r) = cos' (i sin(2)) h(0) = k(0) = 0 Find (a) [2 marks] (f oh)'(0) ( b ) [2 marks) ( ko f )' ( ?) al Sin ( cos ( T'sink] ) + cost ( + since) cos (cost ( rsince) ) flo) = sin ( cost ( Isinto) ) ) + cos? ( Tsiaft) ) cos ( cost ( x- since to)) sin (costco) ) + cost (0) . cos ( cost (0) ) sindij + 1. cos() sin () + cosa) b) *' ( fox) ) f ( sin ( x) + xcos() + 271 ) KI ( #! ) = Sin ( I ) + # 60s(= ] + 271
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