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Problem 1. (1 point) Let f(ac) = - (3x2 + 6Vx). Evaluate the following expressions where h is a variable. - f(25) = -1905 i . f ( 25 + h ): )=-(3(25 + h) 2 + 6V (25 + h ) i Using the explicit function given above, set up, but do not evaluate, the following limits that could be used to find the derivative f'(25). - f'(25) = lim (-(3(25 + h ) 2 + 6V ( 25 + h ) ) +1905) i h +0 h - f' ( 25 ) = lim (-(3x2 + 6VX ) + 1905) i x-25 (x - 25)