Question: Is (x) = x3 exp(-ax) an eigenfunction of the operator = alt + +?? = = dx Yes, and the eigenvalue is - a O

Is (x) = x3 exp(-ax) an eigenfunction of the operator =

Is (x) = x3 exp(-ax) an eigenfunction of the operator = alt + +?? = = dx Yes, and the eigenvalue is - a O Yes, and the eigenvalue is a + 6 O No. Yes, and the eigenvalue is a. Yes, and the eigenvalue is a 6

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