It follows from equation (11.34) of Problem 11.6 that Q=-kT log E=U - TS- uN. Show...

 

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It follows from equation (11.34) of Problem 11.6 that Q=-kT log E=U - TS- uN. Show that [-kT log E (T, , V)] is an extensive variable, so that if the intensive variables T and u are kept constant, (-kT log E) is proportional to the volume V. Hence show that ( log E/V)T, = (log E)/V. Show that equation (11.29) for the pressure p can be rewritten in the form PV = kT log E= -2. It follows from equation (11.34) of Problem 11.6 that Q=-kT log E=U - TS- uN. Show that [-kT log E (T, , V)] is an extensive variable, so that if the intensive variables T and u are kept constant, (-kT log E) is proportional to the volume V. Hence show that ( log E/V)T, = (log E)/V. Show that equation (11.29) for the pressure p can be rewritten in the form PV = kT log E= -2.

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