It is important to give the solution to each scenario (Show addresses and data to be programmed in each case, this table should show all the locations involved in the solution).

Implement the logic function using an 8Kx8 ROM. Solution: Here we see that there is 1 output (Z) and 3 inputs (A, B, and C). We can make the truth table:

Now the corresponding inputs and output are assigned on the address and data lines as shown in the following connection:

Questions:

1. What would change about the exercise if the order of A, B, and C were C, B, and A for A2, A1, and A0 respectively? 2. What would change if we wanted output Z in all data outputs (D0 to D7)? 3. What would change if instead of A3 to A12 being grounded we put them to Vcc?

\begin{tabular}{||c|c|c||c|} \hline A & B & C & F \\ \hline 0 & 0 & 0 & 1 \\ 0 & 0 & 1 & 1 \\ 0 & 1 & 0 & 1 \\ 0 & 1 & 1 & 1 \\ 1 & 0 & 0 & 0 \\ 1 & 0 & 1 & 0 \\ 1 & 1 & 0 & 0 \\ 1 & 1 & 1 & 1 \\ \hline \end{tabular}