Question: It is relatively easy to see that such an algorithm will be quadratic in the overall number of states in the NFA, O ( |
It is relatively easy to see that such an algorithm will be quadratic in the overall number of
states in the NFA, OQ
; in the worst case, each state in Q is visited, and transitions to
every other state in Q are traced.
Based on the runtime of this algorithm, it is possible to prove after all that ANFA in P Give
a proof of this fact.
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