[IV] Use the data in the following table for all parts of this question. (1) (ii)...

 

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[IV] Use the data in the following table for all parts of this question. (1) (ii) X f(x) 3 0.3 0.7306 0.5 0.6055 0.7 0.4865 Approximate f(0.6) by Newton's Divided Difference Formula using 3 nodes Approximate f (0.8) by Newton's Forward-Difference Formula using 2 nodes Approximate f'(0.5) Approximate f" (0.7) by a second derivative midpoint formula [5 Points] 0.9 0.4063 [IV] Use the data in the following table for all parts of this question. (1) (ii) X f(x) 3 0.3 0.7306 0.5 0.6055 0.7 0.4865 Approximate f(0.6) by Newton's Divided Difference Formula using 3 nodes Approximate f (0.8) by Newton's Forward-Difference Formula using 2 nodes Approximate f'(0.5) Approximate f" (0.7) by a second derivative midpoint formula [5 Points] 0.9 0.4063

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Let Newtons divided difference table fxi f fx Xi 05 07 09 06085 04865 04063 07 2209 1 70595 0485 04... View the full answer