Question: Item Gap width (mm) 1 3.253 2 3.254 3 3.248 4 3.247 5 3.249 6 3.249 7 3.250 8 3.249 9 3.246 10 3.249 11
| Item | Gap width (mm) |
| 1 | 3.253 |
| 2 | 3.254 |
| 3 | 3.248 |
| 4 | 3.247 |
| 5 | 3.249 |
| 6 | 3.249 |
| 7 | 3.250 |
| 8 | 3.249 |
| 9 | 3.246 |
| 10 | 3.249 |
| 11 | 3.246 |
| 12 | 3.253 |
| 13 | 3.248 |
| 14 | 3.249 |
| 15 | 3.250 |
| 16 | 3.248 |
| 17 | 3.249 |
| 18 | 3.248 |
| 19 | 3.245 |
| 20 | 3.252 |
| 21 | 3.249 |
| 22 | 3.248 |
| 23 | 3.249 |
| 24 | 3.248 |
| 25 | 3.248 |
| 26 | 3.247 |
| 27 | 3.248 |
| 28 | 3.251 |
| 29 | 3.249 |
| 30 | 3.248 |
| 31 | 3.250 |
| 32 | 3.248 |
| 33 | 3.250 |
| 34 | 3.251 |
| 35 | 3.249 |
| 36 | 3.252 |
| 37 | 3.246 |
| 38 | 3.251 |
| 39 | 3.252 |
| 40 | 3.248 |
Setup for Problems 3 and 4: A critical quality characteristic for purchased part is the width of a gap where another part is inserted. If the gap is too small, the mating part wont fit; if its too large, there will be too much play, resulting in excessive wear. Specifications for the gap width are 3.250.005 mm. These parts are purchased in large lots. From a recent lot, a sample of 40 parts was drawn at random and the gap width determined to the nearest .001 mm. The data look like this (abbreviated table shown)
3. Using the gap width data, develop a histogram of gap width. Comment on the distribution.
4. Using the gap width data, and assuming a normal distribution, estimate the percentage of parts in the population that would fall outside the specification limits.
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