Question: Iterate the initial tableau to optimality. Minimize 5x 1 + 6x 2 Subject to: 1x 1 + 1x 2 = 1000 1x 1 300 +

Iterate the initial tableau to optimality.

Minimize 5x1 + 6x2

Subject to:

1x1 + 1x2 = 1000

1x1 300

+ 1x2 150

Minimize 5x1 + 6x2 + 0S1 + 0S2 + MA1 + MA2 + MA3

Subject to:

1x1 + 1x2 + 1A1 - 1A2 = 1000

1x1 + 1S1 = 300

+ 1x2 - 1S2 + 1A3 = 150

CJ 5 6 0 0 M M M
CB

Basic

Variables

X1 X2 S1 S2 A1 A2 A3 RHS Ratio
M A1 1 1 0 0 1 -1 0 1000
0 S1 1 0 1 0 0 0 0 300
0 S2 0 1 0 -1 0 0 1 150
ZJ M M 0 0 M -M 0 1000M
CJ-ZJ 5-M 6-M 0 0 0 2M M

SOLUTION:

CJ 5 6 0 0 M M M
CB Basic Variables X1 X2 S1 S2 A1 A2 A3 RHS Ratio
ZJ
CJ-ZJ

CJ 5 6 0 0 M M M
CB Basic Variables X1 X2 S1 S2 A1 A2 A3 RHS Ratio
ZJ
CJ-ZJ

CJ 5 6 0 0 M M M
CB Basic Variables X1 X2 S1 S2 A1 A2 A3 RHS Ratio
ZJ
CJ-ZJ

CJ 5 6 0 0 M M M
CB Basic Variables X1 X2 S1 S2 A1 A2 A3 RHS Ratio
ZJ
CJ-ZJ

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