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Question 6) Consider the following two processes that share a common variable X and a semaphore S: // Shared variable int X =2; binary semaphore S = 1; Process P1: Process P2: //initialisation code //initialisation code int Y; int Z; P(S); P(S); P11: Y = 2*X; P21: Z = X+1; = P12: X = Y; P22: X = Z; V(S); V(S); //other code //other code The line numbers P11, P12 and P21, P22 have been added to the left of each statement. How many different values of X are possible after both processes finish executing? What are those values? Explain your answer showing all the possible execution traces. (10 marks)