Question: iv. Angular acceleration of disc Ap Ap' + Acor + Arel Ap -0.51221 + 1.047) m/s^2 Ap'n w^2OP(-cos(theta)i- sin(theta)j) =-0.069081 0.04169j m/s^2 Ap't AlphaOP(-sin(theta)i

iv. Angular acceleration of disc Ap Ap' + Acor + Arel Ap

iv. Angular acceleration of disc Ap Ap' + Acor + Arel Ap -0.51221 + 1.047) m/s^2 Ap'n w^2*OP*(-cos(theta)i- sin(theta)j) =-0.069081 0.04169j m/s^2 Ap't Alpha*OP*(-sin(theta)i + cos(theta)j) =(-0.31i+ 0.5137j) *Alpha m/s^2 Arel Arel* (cos(theta)i + sin(theta)j) = (0.856211 +0.516675j) *Arel m/s^2 Grouping all i-terms: -0.5122 0.09608-0.31*Alpha +0.85621*Arel - 0.38313 -0.03299 -0.31*Alpha + 0.85621*Arel Grouping all j-terms: ---(3) 1.047 -0.04169 +0.5137* Alpha + 0.5167* Arel - 0.63489 0.4538 = 0.5137*Alpha + 0.5167* Arel From (3) and (4): Alpha=0.675976 rad/s^2 Arel=0.206214 m/s^2 ----(4) The angular acc is 0.675976 rad/s^2 and direction is CCW

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Question: iv. Angular acceleration of disc Ap Ap' + Acor + Arel Ap -0.51221 + 1.047) m/s^2 Ap'n w^2*OP*(-cos(theta)i- sin(theta)j) =-0.069081 0.04169j m/s^2 Ap't Alpha*OP*(-sin(theta)i

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Students Have Also Explored These Related Mechanical Engineering Questions!

Question: iv. Angular acceleration of disc Ap Ap' + Acor + Arel Ap -0.51221 + 1.047) m/s^2 Ap'n w^2OP(-cos(theta)i- sin(theta)j) =-0.069081 0.04169j m/s^2 Ap't AlphaOP(-sin(theta)i