Question: (iv) sin2A cos4A = 16 1 cos 2A 32 cos 4A 16 cos 6A 32

(iv) sin2A cos4A = 16 1 cos 2A 32 cos 4A 16

(iv) sin2A cos4A = 16 1 cos 2A 32 cos 4A 16 cos 6A 32

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