IV a) let at time t the instantanioun position, relocity and acceleration of spiderman w.mt net...
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IV a) let at time "t" the instantanioun position, relocity and acceleration of spiderman w.mt net is x(+), x' (+) and x' (+) respectively. hence, we must have mä(t) + kx(+) + 8 X (1)=0 where: ma mass of spider man = 90 kg Ko stifnes constant = 180 N/m 8= damping constant - 270 N/m/s 90x(+) +180 x (+) + 270 x (t).o hot xitle Aewt be the trial solution hence, W² +2+3w=0 W-3 ± √ 9-8 2 w = -1, -2 The general solution is at time vence +=0, x(+)=0 c) at time t=0 Lence, A +213= 25 from the two X (+) = A+B=0 (i) *(t)-Aët_2Bc² 2 2-24 x(+) Ae²+ Be 2+ - 3+1 , x(+) = 25 m/s (1) equations 25 (624pt) we have *(+)+2x (+)+3x² (4) = 0 [A.B are Вс 25, 1-25 integration constants ] b) since x(+) does not contain any oscillation. not also critically damped because the term under the root of W does not the system is over damped. term, hence, it is not underdlamped motion. It is tend to 0 IV a) let at time "t" the instantanioun position, relocity and acceleration of spiderman w.mt net is x(+), x' (+) and x' (+) respectively. hence, we must have mä(t) + kx(+) + 8 X (1)=0 where: ma mass of spider man = 90 kg Ko stifnes constant = 180 N/m 8= damping constant - 270 N/m/s 90x(+) +180 x (+) + 270 x (t).o hot xitle Aewt be the trial solution hence, W² +2+3w=0 W-3 ± √ 9-8 2 w = -1, -2 The general solution is at time vence +=0, x(+)=0 c) at time t=0 Lence, A +213= 25 from the two X (+) = A+B=0 (i) *(t)-Aët_2Bc² 2 2-24 x(+) Ae²+ Be 2+ - 3+1 , x(+) = 25 m/s (1) equations 25 (624pt) we have *(+)+2x (+)+3x² (4) = 0 [A.B are Вс 25, 1-25 integration constants ] b) since x(+) does not contain any oscillation. not also critically damped because the term under the root of W does not the system is over damped. term, hence, it is not underdlamped motion. It is tend to 0 IV a) let at time "t" the instantanioun position, relocity and acceleration of spiderman w.mt net is x(+), x' (+) and x' (+) respectively. hence, we must have mä(t) + kx(+) + 8 X (1)=0 where: ma mass of spider man = 90 kg Ko stifnes constant = 180 N/m 8= damping constant - 270 N/m/s 90x(+) +180 x (+) + 270 x (t).o hot xitle Aewt be the trial solution hence, W² +2+3w=0 W-3 ± √ 9-8 2 w = -1, -2 The general solution is at time vence +=0, x(+)=0 c) at time t=0 Lence, A +213= 25 from the two X (+) = A+B=0 (i) *(t)-Aët_2Bc² 2 2-24 x(+) Ae²+ Be 2+ - 3+1 , x(+) = 25 m/s (1) equations 25 (624pt) we have *(+)+2x (+)+3x² (4) = 0 [A.B are Вс 25, 1-25 integration constants ] b) since x(+) does not contain any oscillation. not also critically damped because the term under the root of W does not the system is over damped. term, hence, it is not underdlamped motion. It is tend to 0 IV a) let at time "t" the instantanioun position, relocity and acceleration of spiderman w.mt net is x(+), x' (+) and x' (+) respectively. hence, we must have mä(t) + kx(+) + 8 X (1)=0 where: ma mass of spider man = 90 kg Ko stifnes constant = 180 N/m 8= damping constant - 270 N/m/s 90x(+) +180 x (+) + 270 x (t).o hot xitle Aewt be the trial solution hence, W² +2+3w=0 W-3 ± √ 9-8 2 w = -1, -2 The general solution is at time vence +=0, x(+)=0 c) at time t=0 Lence, A +213= 25 from the two X (+) = A+B=0 (i) *(t)-Aët_2Bc² 2 2-24 x(+) Ae²+ Be 2+ - 3+1 , x(+) = 25 m/s (1) equations 25 (624pt) we have *(+)+2x (+)+3x² (4) = 0 [A.B are Вс 25, 1-25 integration constants ] b) since x(+) does not contain any oscillation. not also critically damped because the term under the root of W does not the system is over damped. term, hence, it is not underdlamped motion. It is tend to 0
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An Introduction to Measure Theoretic Probability
ISBN: 978-0128000427
2nd edition
Authors: George G. Roussas
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