Question: J. using either rython or MatLab or Octave (or all of the above!) do the following: define a variable a to be equal to 2.6

J. using either rython or MatLab or Octave (or all of the above!) do the following: define a variable a to be equal to 2.6 and print it out to 15 digits after the dot. Then add to it 0.2 and print it again to verify the correctedness of the operation. After adding 0.2 to a three times you will see the appearance of an error, explain why. What happend if. instead, you add directly 0.6 to 2.6? Why? 1. Consider a Floating point system with base 10 and 3 digits mantissa (namely significant digits) and evaluate 3(4/3- 1)-1 in that system. 2. Do the same for single and double precision standard floating point numbers. J. using either rython or MatLab or Octave (or all of the above!) do the following: define a variable a to be equal to 2.6 and print it out to 15 digits after the dot. Then add to it 0.2 and print it again to verify the correctedness of the operation. After adding 0.2 to a three times you will see the appearance of an error, explain why. What happend if. instead, you add directly 0.6 to 2.6? Why? 1. Consider a Floating point system with base 10 and 3 digits mantissa (namely significant digits) and evaluate 3(4/3- 1)-1 in that system. 2. Do the same for single and double precision standard floating point numbers
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