Question: Jack, Steve, and John return from their latest heist with five indivisible gold bars. They must decide who gets how many, and according the well-established

Jack, Steve, and John return from their latest heist with five indivisible gold bars. They must decide who gets how many, and according the well-established Code of Thieves, they follow this procedure to decide who gets the gold bars:

a.Jack proposes some split of the gold bars. Each person can only receive a whole number of gold bars (0, 1, 2, 3, 4, or 5) and all 5 gold bars must be allocated.

b.Steve and John vote on whether to accept Jack's split. If at least one of them agrees to it, then that split is enacted, and the game ends. If they disagree, Jack dies, one gold bar is used to pay for her funeral, and the game continues to part c.

c.Steve proposes a split of the 4 remaining gold bars. If John agrees, then they split the bars as Zane proposed; otherwise, Zane dies, 1 gold bar is used to pay for his funeral, and John receives the remaining 3 gold bars.

Each person wants to live, and to receive as many gold bars as possible. Additionally, if they will receive the same number of gold bars either way, they prefer to minimize the number of funerals.

What is the subgame perfect Nash equilibrium.

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