java

Assume that you are implementing a program to find 'superb numbers. A number is a superb number if it can be divided by each and everyone of its digits without any remainders For example 126 is a superb number because 126 can be divided by 1, 2 and 6 without any remainders. 123 is not a superb number because it is not divisible by the digit2 Do not consider the digit "O" as a divisor. If a number contains it is not a superb number TO DO: Develop a method called issuperb that returns true if the given integer argument possitive integer number) is a superb number, false otherwise Develop a method called getFirstSuperbNumbers that gets 2 integer (possitive integers) arguments lets call them startValue and number ofValues. First Integer argument startValue is the starting value and the second integer argument, number o/Values, is the number of values. getFirstSuperbNumbers method returns an Integer array back having number of values elements that are the first numberofolues superb numbers that are greater than or equal to the startValue. . For example, if we call getFirstSuperbNumbers/20,3) . startValue - 20, numberOlValues=3, which means the returned array should contain first 3 superb numbers that are greater than or equal to 20. These are 22,24,33 Hint you need to use is Superb method