Java

C#

abstract class A $\{$

private int x;

public A$()\{$

x$=7$;

$\}$

public A$($int y$)\{$

x$=$y;

$\}$

public abstract int do$\_$stuff$1()$;

public abstract int do$\_$stuff$2()$;

$\}$

class B extends A $\{$

public B$()\{$

super$(7)$;

$\}$

public B$($int y$)\{$

super$($y$)$;

$\}$

@Override

public int do$\_$stuff$1()\{$

return $4$;

$\}$

@Override

public int do$\_$stuff$2()\{$

return $4$;

$\}$

$\}$

class Main $\{$

public static void main$($String$[]$ args$)\{$

B myB $=$ new B$(5)$;

$\}$

$\}$

using System;

abstract class A $\{$

private int x;

public A$()\{$

x$=7$;

$\}$

public A$($int y$)\{$

x$=$y;

$\}$

public abstract int do$\_$stuff$1()$;

public abstract int do$\_$stuff$2()$;

$\}$

class B : A $\{$

public B$()$ : base$(7)\{$

$\}$

public B$($int y$)$ : base $($y$)\{$

$\}$

public override int do$\_$stuff$1()\{$

return $4$;

$\}$

public override int do$\_$stuff$2()\{$

return $4$;

$\}$

$\}$

class MainClass $\{$

public static void Main $($string$[]$ args$)\{$

B myB $=$ new B$(5)$;

$\}$

$\}$

Question $8$ options:

No$,$ class A cannot have a constructor since it's abstract$.$

No$,$ class B can't have a constructor since it's inheriting from an abstract class A$.$

No$,$ you can't use super$/$base to call a constructor in an abstract class.

Yes