JAVA Code:

Complete the method sumOfDigits() that computes the sum of the digits of the given positive integer argument, n

e.g., if n = 5403, the method will return: 5+4+0+3 = 12 note: the right-most (1's) digit can be found using n%10 (5403 % 10 is 3, for example) the remaining digits (all but the 1's digit) can be found using n/10 (5403 / 10 is 540, for example)

Starter Code:

public class Digits { public static int sumOfDigits(int n) { //TODO: complete this method } }