Java help /*** 10.22 (a) A point is inside the triangle. (b) A triangle is inside another triangle. (c) A triangle overlaps another triangle. Draw the UML diagram for the class and then implement the class. Write a test program that creates a Triangle2D objects t1 using the constructor new Triangle2D(new MyPoint(2.5, 2), new MyPoint(4.2, 3), new MyPoint(5, 3.5)), displays its area and perimeter, and displays the result of t1.contains(3, 3), r1.contains(new Triangle2D(new MyPoint(2.9, 2), new MyPoint(4, 1), MyPoint(1, 3.4))), and t1. overlaps(new Triangle2D(new MyPoint(2, 5.5), new MyPoint(4,-3), MyPoint(2, 6.5))).

I don\'t have the Programming Exercise 2.19 or Exercise 3.25

(Hint: For the formula to compute the area of a triangle, see Programming Exercise 2.19. To detect whether a point is inside a triangle, draw three dashed lines, as shown in Figure 10.23. If the point is inside a triangle, each dashed line should intersect a side only once. If a dashed line intersects a side twice, then the point must be outside the triangle. For the algorithm of finding the intersecting point of two lines, see Programming Exercise 3.25.) */ Note -Neha Khanna answered this but I could not use because I did not have other Exercise

*3.25 (Geometry: intersecting point) Two points on line 1 are given as (x1, y1) and (x2,

y2) and on line 2 as (x3, y3) and (x4, y4), as shown in Figure 3.8ab.

The intersecting point of the two lines can be found by solving the following

linear equation:

(y1 - y2)x - (x1 - x2)y = (y1 - y2)x1 - (x1 - x2)y1

(y3 - y4)x - (x3 - x4)y = (y3 - y4)x3 - (x3 - x4)y3

This linear equation can be solved using Cramers rule (see Programming Exercise

3.3). If the equation has no solutions, the two lines are parallel (Figure 3.8c).

and this exercise