Question: java Private static void mystery 1(Natural Number[] arr) { arr[0] - new Natural Number lL(2); arr[l].multiply(arr[0]) private static void mystery2(NaturalNumber n1) {nl.increment(); n1 = new

java  java Private static void mystery 1(Natural Number[] arr) { arr[0] -

Private static void mystery 1(Natural Number[] arr) { arr[0] - new Natural Number lL(2); arr[l].multiply(arr[0]) private static void mystery2(NaturalNumber n1) {nl.increment(); n1 = new NaturalNuaber1 L(5); private static void mystery3(String s1) { s1 = s1. substring(2); s1 = s1 + s1; public static void main(String[] args) { Natural Number[] nums = new Natural Number[2]; nums[0] = new NaturalNuaberll(l); nums[l] = new NaturalNuaberlL(2); NaturalNumber a = new NaturalNumberll(3); NaturalNumber b = new NaturalNumberlL(4); String s - "Ohio"; b.add(b.divide(nums[l])); mysteryl(nums); mystery2(a); mystery 3 (s); } Refer to the code provided above. When the program ends, what will be the final value of the variable, b? b = 6 b = 4 b = 2 b = 8 Refer to the code provided above. When the program ends, what will be the final value of the elements in the nuns array? nums [0] = 1, nums [1] = 2 nums [0] = 2, nums [1] = 2 nums [0] = 1, nums [1] = 4 nums [0] = 2, nums [1] = 4 Refer to the code provided above. When the program ends, what will be the final value of the variable, a? a = 5 a = 4 a- 3 a = 6 Refer to the code provided above. When the program ends, what will be the final value of the variable, s? s = Ohio" s = "ioio" s = OhOh" s- "OhioOhio

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