JAVA Write a public class call FunnyWord. class FunnyWord must have a main method. what it does: 0. prompt user for a String 1. read a String from the user 2. print whether the String is funny or not 3. continue until user enters the word "end" The String is funny if it looks the same read from left to right or right to left. In order to pass all tests you must find funny phrases when spaces, punctuation and case are ignored (look at the examples). HINT: you could use the method replaceAll from String in order to delete all the punctuation marks. For example: str.replaceAll(";", ""); returns a string where all semicolons have been replaced by nothing. or you could use str.replaceAll("\\W","") which replaces all punctuation marks you may also need other methods of String: toLowerCase(): returns another String in lower case length(): gives you the length of the String you can build a String character by character this way: char c; String rr; rr = rr + c; //adds the c at the end of rr here is a piece of code that uses some of these methods: public class Traverse{ public static void main(String [] aaa){ String ss = "x y z a b.?/;:'[{]} c defgh"; ss = ss.replaceAll("\\W",""); String new1 = ""; String new2 = ""; for (int i = 0; i < ss.length(); i++){ new1 = new1 + ss.charAt(i); new2 = ss.charAt(i) + new2; } System.out.println(new1); System.out.println(new2); } } Notice: you cannot use any method called "reverse". That is considered forbidden knowledge. 

Examples

% java FunnyWord Enter a String: Anna

funny!

Enter a String: AnnA AnnA

funny!

Enter a String: A man, a plan, a canal: Panama.

funny!

Enter a String: foo

that is not funny

Enter a String: Annax

that is not funny

Enter a String: end

that is not funny