Question: Jaywalking is a huge safety issue in Oxford, often causing cars to get into accidents. Use the data below to establish hypotheses and calculate the
- Jaywalking is a huge safety issue in Oxford, often causing cars to get into accidents. Use the data below to establish hypotheses and calculate the ANOVA for the relationship between age and number of citations for jay walking. State and explain your decision with regard to whether the H0 is ultimately rejected or retained.
| 18-30 | 31-50 | 50+ |
| 4 | 1 | 5 |
| 3 | 0 | 6 |
| 5 | 0 | 6 |
| 4 | 1 | 4 |
| 5 |
Step 1: State the Ho and the H1.
H0:
H1:
Step 2: Identify the distribution and compute the df.
The distribution is _______ distribution.
dfB=
dfW =
Step 3: Identify the critical value of the test statistic and state the decision rule.
=
critical value =
Step 4: Review the obtained value of the test statistic.
| Age Group | |||||
| 18-30 (x1) | x12 | 31-50 (x2) | x22 | 50+ (x3) | x32 |
| 4 | 16 | 1 | 1 | 5 | 25 |
| 3 | 9 | 0 | 0 | 6 | 36 |
| 5 | 25 | 0 | 0 | 6 | 36 |
| 4 | 16 | 1 | 1 | 4 | 16 |
| 5 | 25 | ||||
| n1= 4 | n2= 4 | n3= 5 | |||
Grand Mean:
Total Sums of Squares:
Between-groups Sums of Squares:
= 4(4 - 3.38)2 + 4(0.5 - 3.38)2 + 5(5.2 - 3.38)2
= 4(0.62)2 + 4(-2.88)2+ 5(1.82)2
= 4(0.3844) + 4(8.2944) + 5(3.3124)
= 1.54 + 33.18 + 16.56 = 51.28
Within-groups Sums of Squares:
SSW= SST- SSB= 57.08 - 51.28 = 5.8
Compute the Mean Squares:
MSB=
MSW=
Compute the F statistic:
Fobt=
Step 5: Make a decision about the null and state the substantive conclusion.
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