Question: JLUS 12 > MIDTERM EXAM > MIDTERM EXAM - WRITTEN > EXAM 4 5 QUESTION 1 9:27 Find a value of m so that when

 JLUS 12 > MIDTERM EXAM > MIDTERM EXAM - WRITTEN >EXAM 4 5 QUESTION 1 9:27 Find a value of m sothat when x4 - mx3 - 3x2 + 4x - 12 isdivided x + 2 the remainder is-40. File Edit View Insert "Format . Tools Table KA Verdana 11pt A A C - out

of 3 Next pageYouTube YER PRE-CALCULUS 12 > MIDTERM EXAM . MIDTERMEXAM - WRITTEN . EXAM 2 3 4 5 QUESTION 4 Pme Left 00:58:56 Solve 10g6(7) - 1) - 10g61 = 10g62for j.File . Edit . View - Insert - Format * Tools -Table KX Verdana 11pt A B / Y 3 3 5 8

JLUS 12 > MIDTERM EXAM > MIDTERM EXAM - WRITTEN > EXAM 4 5 QUESTION 1 9:27 Find a value of m so that when x4 - mx3 - 3x2 + 4x - 12 is divided x + 2 the remainder is-40. File Edit View Insert " Format . Tools Table KA Verdana 11pt A A C - out of 3 Next pageYouTube YER PRE-CALCULUS 12 > MIDTERM EXAM . MIDTERM EXAM - WRITTEN . EXAM 2 3 4 5 QUESTION 4 P me Left 00:58:56 Solve 10g6(7) - 1) - 10g61 = 10g62for j. File . Edit . View - Insert - Format * Tools - Table KX Verdana 11pt A B / Y 3 3 5 8 3 - E- - out of 3 Previous page Next pagePRE-CALCULUS 12 > MIDTERM EXAM > MIDTERM EXAM - WRITTEN > EXAM > 2 3 4 5 QUESTION 2 Left 00:59:12 Sketch y = - 2 on the grid provided. Show the y-intercept. 5. - 5 -S File - Edit - View Insert Format Tools Table3 4 5 QUESTION 5 1 00:58:51 Describe the transformation the graph on the leftundergoes to become the graph on the right. File - Edit - View . Insert - Format - Tools - Table - Verdana 11pt A - A - - out of 3 Previous pageUS 12 > MIDTERM EXAM . MIDTERM EXAM - WRITTEN . EXAM 5 QUESTION 3 Graph the rational function: y = - x2 +3x -on the grid below. State the coordinates of x2+5x+6 the x and y intercepts and the domain. Label the equations of the asymptotes. File - Edit - View - Insert Format - Tools - Table Verdana 11pt A- A - B / Y = = = = 6 6 . B

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