Jose continues his hypothesis test, by finding critical values and making a conclusion about the null hypothesis.

• H
• 0
• :=1.9
• ;H
• a
• :>1.9
• , which is a right-tailed test.
• =0.05
• .
• z
• 0
• =3.88

Which is the correct conclusion of Jose'sone-mean hypothesis test at the5%

significance level?

Use the Standard Normal Table for the critical values:

z

0.10

z

0.05

z

0.025

z

0.01

z

0.005

1.282

1.645

1.960

2.326

2.576

Select the correct answer below:

Critical value:z

0.05

=1.645

We should rejectH

0

becausez

0

>z

0.05

. So, at the5%

significance level, the data provide sufficient evidence to conclude that the new bat helped Jose increase his average hits per game.

Critical value:z

0.05

=1.645

We shouldnotrejectH

0

becausez

0

0.05

.So, at the5%

significance level, the data does not provide sufficient evidence to conclude that the new bat helped Jose increase his average hits per game.

Critical value:z

0.005

=2.576

We should rejectH

0

becausez

0

>z

0.05

.So, at the5%

significance level, the data provide sufficient evidence to conclude that the new bat helped Jose increase his average hits per game.

Critical value:z

0.05

=1.645

We shouldnotrejectH

0

becausez

0

>z

0.05

.So, at the5%

significance level, the data doest not provide sufficient evidence to conclude that the new bat helped Jose increase his average hits per game.

Critical values:z

0.05

=1.645

andz

0.05

=1.645

We should rejectH

0

becausez

0

>z

0.05

.So, at the5%

significance level, the data provide sufficient evidence to conclude that the new bat helped Jose increase his average hits per game.