Question: $jsonData = ' { name : John, age: 3 0 , email: john@example.com } ' ; $data = json _ decode ( $jsonData,
$jsonData name: "John", "age": "email": "john@example.com";
$data jsondecode$jsonData, true;
You can access the name field from the decoded JSON data using $dataname.
Select one:
True
False
Step by Step Solution
There are 3 Steps involved in it
1 Expert Approved Answer
Step: 1 Unlock
Question Has Been Solved by an Expert!
Get step-by-step solutions from verified subject matter experts
Step: 2 Unlock
Step: 3 Unlock
