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Compute: $d=b^3+c^2$

Click here for example

Ex: If the input is:

$2\mathrm{.}0$

$4\mathrm{.}0$

then the output is:

$d=24\mathrm{.}0$

import math

b $=$ float$($input$())$

c $=$ float$($input$())$

$\backslash$

print$($f$\text{'}$d $=\{$d:$\mathrm{.}1$f$\}\text{'})$ # Outputs d with $1$ decimal place