just explaining about procedure will be enough

[SADT'I 2] Say you have a bunch of data points (221-, yi) ,1" = 1, . . . and wish to draw the line of best t through them. The given points do not all fall on the same straight line but you can nd the gradient m and intercept 1: such the line best 'ts' the given points (see gure). Figure for [SADT12] Now let CL; = y,' (mm; + bbe the vertical deviation of (mi, yfrom the line. To obtain the best t line. we want to minimize n 2 d3. i=1 Prove that the line of best t is obtained when n 11. 111.2% +bn = 2y; i=1 i=1 and n n n '1'\".ng + 52131: = 223%. i=1 i=1 i=1 DO NOT USE LAGRANGE MULTIPLIERS FOR THIS