Question: k = 1 , min = 0 2 for i = 1 to A . length 3 min = A [ i ] 4 for

k=1,min =0
2 for i=1 to A.length
3 min = A[i]
4 for j= i+1 to A.length
5 if min>A[i]
6 min = A[i]
7 k=j
8 if A[i]> min
9 swap (A[i], A[k])
Think of two scenarios where you need to compute the lower bound and upper bound of
the Selection Sort Algorithm given below.

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