"Keeping C₁ constant at C₁=5, the interval for the net change in C₂, represented by C₂, while the current optimal solution remains optimal is"

Crammer Tools, LLC. makes two products. The availability of three scarce resources limits the production of the products. The profit contribution, resource usage per unit of each product, and availabilities of the resources are given in the following table. Resource 1 3 Resource Usage per Unit Product 1 Product 2 2 2 6 7 5 4 Availability 180 100 420 2 3 Profit Contribution The decision variables used in the linear programming model are X - number of units of product 1 to produce xz - number of units of product 2 to produce The linear programming model and the graphic solution are given in the following max 5x + 4x2 s.. WA 3 x1 + 2 x S 180 1 xy + 2x2 5 100 6 x + 7x2 S 420 X1, X20 100 90 80 Feasible region 70 20 60 50 60 40 Optimal solution 140 50 30 20 20 40 10 10 20 30 60 70 80 20 40 SO 5x + 4xy - 2009 32+2x - 180 90 100 110 6 + 7 = 420 4+2 = 100 QUESTION 28 Keeping C constant at C1 = 5, the interval for the ne change in Cz, represented by Acy, while the current optimal solution remains optimalis 11 11 6 os-4c255 sacs- & sacs / o sucesso 10 3 none of the above