Kevin is refinishing his rusty wheelbarrow. He moves his sandpaper back and forth $45$ times over a rusty area, each time moving a total distance of $0\mathrm{.}15$ m$.$ Kevin pushes the sandpaper against the surface with a normal force of $1\mathrm{.}8$ N$.$ The coefficient of friction for the metal$/$sandpaper interface is $0\mathrm{.}92.$ How much work is done by the kinetic frictional force during the sanding process?

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Answer Now we can calculate the work done by the kinetic frictional force W165601545cos180W165601... View the full answer