Question: Killing Lambda - moves In the construction of Section 1 4 . 7 , we change the start state to a final state if

Killing Lambda-moves
In the construction of Section 14.7, we change the start state to a final state if \lambda is in L(M), but do not change the final state set in any other way. Suppose that instead we changed the final state set to include all states with \lambda -paths to an existing final state. Then the resulting ordinary NFA would still have the same language as the original \lambda -NFA. true or false

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