Kindly explain the step-by-step procedure on how it came up with 21 m/s as final answer. Explain intelligently.

A 1.50 kg snowball is fired from a cliff 12.5 m high. The snowball's initial velocity is 14.0 m/s, directed 41.0 above the horizontal. Using conservation of mechanical energy, calculate the speed of the snowball as it reaches the ground below the cliff.

Answer:

Given : macs of the snowball ( m ) = 1.50 kg height of the cliff Ch ) - 12.5 m Initial velocity (u ) =14 m/s acceleration due to gravity ( 9 9-8 m/s * angle of projection ( 4 ) = 410 Formula! according to the law of conversation of energy = = mu" = I mu" + mah or V' = u2 + 2gh or V = Ju2 + 2gh Solution : V : J U 2 + 2gh V = ( 14. 0m/s ) 2 + 2 (9.8 mls) ( 12.5 m ) V z 196mls2 + 245 m/12 y 441 mls 2 V z 21 mis