Question: #knowns Theta _ 2 = ( 3 7 * np . pi ) / 1 8 0 R _ OA = 2 R _ AB

#knowns
Theta_2=(37*np.pi)/180
R_OA=2
R_AB=4.5
R_CB=3.1
R_OC=4
R_AP=2.5
ALPHA=(27*np.pi)/180
# Define the equations as functions
def equations(vars):
Theta_3, Theta_4= vars
eq1=-R_OA * np.cos(Theta_2)+ R_AB * np.cos(Theta_3)- R_CB * np.cos(Theta_4)- R_OC * np.cos(0)
eq2=-R_OA * np.sin(Theta_2)+ R_AB * np.sin(Theta_3)- R_CB * np.sin(Theta_4)- R_OC * np.sin(0)
# eq1= r_O2A * np.cos(Theta_O2A)+ r_AB * np.cos(Theta_AB)- r_O4B * np.cos(Theta_O4B)- r_O2O4* np.cos(0)
# eq2= r_O2A * np.sin(Theta_O2A)+ r_AB * np.sin(Theta_AB)- r_O4B * np.sin(Theta_O4B)- r_O2O4* np.sin(0)
return [eq1, eq2]
# Initial guesses for x and y (in radians)
initial_guess =[(15*np.pi)/180,(50*np.pi)/180]
# Theta 3 Theta 4
# Solve the system of equations
solution = fsolve(equations, initial_guess)
# Convert the solution to degrees for better readability
solution_degrees = np.degrees(solution)
# Display the solutions
# print(f"Solution in radians: Theta_AB ={solution[0]}, Theta_O4B ={solution[1]}")
print(f"Solution in degrees: Theta_3={solution_degrees[0]}, Theta_O4={solution_degrees[1]}")

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