Question: L 1 = {x {a,b}* | aa is not a substring of x}; L 2 = {x {a, b}* | x ends with ab}. For

L1 = {x L1 = {x {a,b}* | aa is not a substring of x}; {a,b}* | aa is not a substring of x}; L2 = {x L2 = {x {a, b}* | x ends with ab}. For the {a, b}* | x ends with ab}. For the FA that accepts L1FA that accepts L1L2 , prove that there cannot be any otherL2 , prove that there cannot be any other FA with fewer states accepting the same language.FA with fewer states accepting the same language.

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