$ln(\frac{P_2}{P_1})=(\frac{H_{\text{e}\text{o}\text{p}}}{R})(\frac{1}{T_1}-\frac{1}{T_2})$

A compound has a vapor pressure of $137$ torr or $mmHg)$ at $45\mathrm{.}4.C.$ What is the normal boiling point of the compound? The enthalpy of vaporization of the compound is

$31\mathrm{.}77k\frac{J}{m}ol.,R=8\mathrm{.}3145\frac{J}{m}$olK. Make sure to convert temperature to Kelvin.

$C$