${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{ln(x)}{x}dx$

$u=ln(x)$;$dv=\frac{1}{x^2}dx{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}{x}^4\sqrt[\phantom{2}]{x^3+9}dx$

$u=x^2$;$dv=x^2\sqrt[\phantom{2}]{x^3+9}dx$