LAB 5.3 Working with the for loop Bring the for.cpp from the Lab 5 folder. This program

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Question:

LAB 5.3 Working with the for loop

Bring the for.cpp from the Lab 5 folder. This program has the user input a number n and then finds the mean of the first n positive integers. ??

The code is shown below:

// This program has the user input a number n and then finds the

// mean of the first n positive integers

// PLACE YOUR NAME HERE

#include

using namespace std;

int main()

{

? ? ? int value; ? ? ? // value is some positive number n

? ? ? int total = 0; ? // total holds the sum of the first n positive numbers

? ? ? int number; ? ? ?// the amount of numbers

? ? float mean; ? ? ?// the average of the first n positive numbers

? ? cout

? ? ? cin >> value;

? ? if (value > 0)

? ? {

? ? ? ? ? ? for (number = 1; number

? ? ? ? {

? ? ? ? ? ? ? total = total + number;

? ? ? ? ? ? } // curly braces are optional since there is only one statement

? ? ? ? ? ?

? ? ? ? mean = static_cast(total) / value; ? ? ? ? // note the use of the typecast

? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?// operator here

? ? ? ? ? ? cout

? ? ? ? ? ? ?

? ? }

? ? else

? ? ? ? cout

? ?return 0; ? ??

}

Exercise 1 : Why is the typecast operator needed to compute the mean in the statement mean = static_cast(float)(total)/value? What do you think will happen if it is removed? Modify the code and try it. Record what happens. Make sure that you try both even and odd cases. Now put static_cast total back in the program.

Sample Run :

CAUsersleleel DesktopHands-on 1Debug)Hands-on 1.exe Please enter a positive integer 10 The mean average of the first 10 positive integers is 5.5 Press any key to continue .. .

Exercise 2 : What happens if you enter a float such as 2.99 instead of an integer for value? Try it and record the results.

Exercise 3 : Modify the code so that it computes the mean of the consecutive positive integers n, n+1, n+2, ?, m, where the use choose n and m, For example, if the use picks 3 and 9, then the program should find the mean of 3, 4, 5, 6, 7, 8, and 9, which is 6.