Language: C Programming

*Solve with solution not having to be in the main()*

Source Code:

#include

int is_consonant(char ch);

int main(void)

{

char ch;

for (ch = 91; ch

{

printf("is_consonant('%c'): %d ", ch, is_consonant(ch));

}

return 0;

}

Output:

1 is_consonant('': e 2 is_consonant(\'): 0 3 is_consonant']'): 0 onant(': 0 3 is con 4 is cons 5 is con is_consonant(_"): is. consonant('') : 0 7 is_consonant('a): 8 is_consonant("b') 1 9 is_consonant('c'):1 10 is consonant('d': 1 11 is_consonant('e"): 0 12 is consonant('f: 1 13 is consonant(g'): 1 14 is consonant('h'): 1 15 is_consonant('i'): 0 16 is_consonant(j): 1 17 is consonant('k'): 1 18 is_consonant('l'): 1 19 is_consonant('m) 1 20 is_consonant('n) 1 21 is_consonant('o) 0 22 is_consonant( p'): 1 23 is consonant('a': 1 24 is_consonant("r'): 1 25 is_consonant( s" 1 26 is consonant('t': 1 27 is_consonant ('u): 28 is_consonant('v) 1 29 is_consonant('w'): 1 30 is_consonant('x'"): 1 31 is_consonant('y): 1 32 is_consonant('z'): 1 33 is_consonant(': 0 34 is_consonant(): 0 35 is_consonant(): 0 36 is_consonant(" 0