Language/Platform The project must be written in C, C++, or Java. If using C or C++,...

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Language/Platform The project must be written in C, C++, or Java. If using C or C++, you must use a Unix fork to create processes and a Unix pipe for communication. If using Java, you must use the Runtime exec method to create processes and streams for communication. Your project will receive no credit if not using processes or if using threads instead of processes. All code must run successfully on our cs1.utdallas.edu server or csgrads1.utdallas.edu server. Any other method requires instructor approval. Problem Overview The project will simulate a simple computer system consisting of a CPU and Memory. The CPU and Memory will be simulated by separate processes that communicate. Memory will contain one program that the CPU will execute and then the simulation will end. Objectives 1) Learn how multiple processes can communicate and cooperate. 2) Understand low-level concepts important to an operating system. a. Processor interaction with main memory. b. Processor instruction behavior. c. Role of registers. d. Stack processing. e. Procedure calls. Problem Details f. System calls. g. Interrupt handling. h. Memory protection. I/O. 1. j. Virtualization/emulation CPU It will have these registers: PC, SP, IR, AC, X, Y. It will support the instructions shown on the next page of this document. It will run the user program at address 0. Instructions are fetched into the IR from memory. The operand can be fetched into a local variable. Each instruction should be executed before the next instruction is fetched. The user stack resides at the end of user memory and grows down toward address 0. The system stack resides at the end of system memory and grows down toward address 0. There is no hardware enforcement of stack size. The program ends when the End instruction is executed. The 2 processes should end at that time. The user program cannot access system memory (exits with error message). read(address) returns the value at the address write(address, data) - writes the data to the address Memory It will consist of 2000 integer entries, 0-999 for the user program, 1000-1999 for system code. It will support two operations: Memory will initialize itself by reading a program file. Note that the memory is simply storage; it has no real logic beyond reading and writing. Timer A timer will interrupt the processor after every X instructions, where X is a command-line parameter. Interrupt processing There are two forms of interrupts: the timer and a system call using the int instruction. In both cases the CPU should enter kernel mode. The stack pointer should be switched to the system stack. SP and PC registers should be saved on the system stack. (The handler may save additional registers). A timer interrupt should cause execution at address 1000. The int instruction should cause execution at address 1500. The iret instruction returns from an interrupt. Interrupts should be disabled during interrupt processing to avoid nested execution. To make it easy, do not allow interrupts during system calls or vice versa. Instruction set 1 = Load value 2 = Load addr 3 = LoadInd addr 4 = LoadIdxX addr 5 = LoadIdxY addr 6 = LoadSpX 7 = Store addr 8 = Get 9 = Put port 10 = AddX 11 = Addy 12 = SubX 13 = Suby 14 = CopyToX 15 = CopyFromX 16 = CopyToY 17 = CopyFrom Y 18 = CopyToSp 19 = CopyFromSp 20 = Jump addr 21 = JumpIfEqual addr 22 JumpIfNotEqual addr 23 = Call addr 24 = Ret 25 = IncX 26 = DecX 27 Push 28 = Pop 29 = Int 30 IRet 50 End = Load the value into the AC Load the value at the address into the AC Load the value from the address found in the given address into the AC (for example, if LoadInd 500, and 500 contains 100, then load from 100). Load the value at (address+X) into the AC (for example, if LoadIdxX 500, and X contains 10, then load from 510). Load the value at (address+Y) into the AC Load from (Sp+X) into the AC (if SP is 990, and X is 1, load from 991). Store the value in the AC into the address Gets a random int from 1 to 100 into the AC If port=1, writes AC as an int to the screen If port=2, writes AC as a char to the screen Add the value in X to the AC Add the value in Y to the AC Subtract the value in X from the AC Subtract the value in Y from the AC Copy the value in the AC to X Copy the value in X to the AC Copy the value in the AC to Y Copy the value in Y to the AC Copy the value in AC to the SP Copy the value in SP to the AC Jump to the address Jump to the address only if the value in the AC is zero Jump to the address only if the value in the AC is not zero Push return address onto stack, jump to the address Pop return address from the stack, jump to the address Increment the value in X Decrement the value in X Push AC onto stack Pop from stack into AC Perform system call Return from system call End execution Don't add to this list without approval Input File Format Each instruction is on a separate line, with its operand (if any) on the following line. The instruction or operand may be followed by a comment which the loader will ignore. Anything following an integer is a comment, whether or not it begins with //. A line may be blank in which case the loader will skip it without advancing the load address. A line may begin by a period followed by a number which causes the loader to change the load address. Your program should run correctly with the any valid input files. Sample Programs The input program filename and timer interrupt value should be command line arguments, for example: java Project1 program.txt 30 Here are two sample programs for illustration purposes: This program gets 3 random integers and sums them, then prints the result. Note that each line only has one number. 8 // Get 14 // CopyToX 8 // Get 16 // CopyToY 8 // Get 10 // AddX 11 // AddY 9 / Put 1 1 50 // End This program prints HI followed by a newline to the screen. To demonstrate a procedure call, the newline is printed by calling a procedure. 1 // Load 72=H 72 9 // Put 2 2 1 // Load 73=I 73 9 // Put 2 2 23 / Call 11 11 50 // End 1 // Load 10=newline 10 9 // Put 2 2 24 // Return Language/Platform The project must be written in C, C++, or Java. If using C or C++, you must use a Unix fork to create processes and a Unix pipe for communication. If using Java, you must use the Runtime exec method to create processes and streams for communication. Your project will receive no credit if not using processes or if using threads instead of processes. All code must run successfully on our cs 1.utdallas.edu server or csgrads1.utdallas.edu server. Any other method requires instructor approval. Problem Overview The project will simulate a simple computer system consisting of a CPU and Memory. The CPU and Memory will be simulated by separate processes that communicate. Memory will contain one program that the CPU will execute and then the simulation will end. Objectives 1) Learn how multiple processes can communicate and cooperate. 2) Understand low-level concepts important to an operating system. a. Processor interaction with main memory. b. Processor instruction behavior. c. Role of registers. d. Stack processing. e. Procedure calls. Problem Details f. System calls. g. Interrupt handling. h. Memory protection. I/O. 1. j. Virtualization/emulation CPU It will have these registers: PC, SP, IR, AC, X, Y. It will support the instructions shown on the next page of this document. It will run the user program at address 0. Instructions are fetched into the IR from memory. The operand can be fetched into a local variable. Each instruction should be executed before the next instruction is fetched. The user stack resides at the end of user memory and grows down toward address 0. The system stack resides at the end of system memory and grows down toward address 0. There is no hardware enforcement of stack size. The program ends when the End instruction is executed. The 2 processes should end at that time. The user program cannot access system memory (exits with error message). read(address) returns the value at the address write(address, data) - writes the data to the address Memory It will consist of 2000 integer entries, 0-999 for the user program, 1000-1999 for system code. It will support two operations: Memory will initialize itself by reading a program file. Note that the memory is simply storage; it has no real logic beyond reading and writing. Timer A timer will interrupt the processor after every X instructions, where X is a command-line parameter. Interrupt processing There are two forms of interrupts: the timer and a system call using the int instruction. In both cases the CPU should enter kernel mode. The stack pointer should be switched to the system stack. SP and PC registers should be saved on the system stack. (The handler may save additional registers). A timer interrupt should cause execution at address 1000. The int instruction should cause execution at address 1500. The iret instruction returns from an interrupt. Interrupts should be disabled during interrupt processing to avoid nested execution. To make it easy, do not allow interrupts during system calls or vice versa. Instruction set 1 = Load value 2 = Load addr 3 = LoadInd addr 4 = LoadIdxX addr 5 = LoadIdxY addr 6 = LoadSpX 7 = Store addr 8 = Get 9 = Put port 10 = AddX 11 = Addy 12 = SubX 13 = Suby 14 = CopyToX 15 = CopyFromX 16 = CopyToY 17 = CopyFrom Y 18 = CopyToSp 19 = CopyFromSp 20 = Jump addr 21 = JumpIfEqual addr 22 = JumpIfNotEqual addr 23 = Call addr 24 = Ret 25 = IncX 26 = DecX 27 Push 28 = Pop 29 = Int 30 IRet 50 End = Load the value into the AC Load the value at the address into the AC Load the value from the address found in the given address into the AC (for example, if LoadInd 500, and 500 contains 100, then load from 100). Load the value at (address+X) into the AC (for example, if LoadIdxX 500, and X contains 10, then load from 510). Load the value at (address+Y) into the AC Load from (Sp+X) into the AC (if SP is 990, and X is 1, load from 991). Store the value in the AC into the address Gets a random int from 1 to 100 into the AC If port=1, writes AC as an int to the screen If port=2, writes AC as a char to the screen Add the value in X to the AC Add the value in Y to the AC Subtract the value in X from the AC Subtract the value in Y from the AC Copy the value in the AC to X Copy the value in X to the AC Copy the value in the AC to Y Copy the value in Y to the AC Copy the value in AC to the SP Copy the value in SP to the AC Jump to the address Jump to the address only if the value in the AC is zero Jump to the address only if the value in the AC is not zero Push return address onto stack, jump to the address Pop return address from the stack, jump to the address Increment the value in X Decrement the value in X Push AC onto stack Pop from stack into AC Perform system call Return from system call End execution Don't add to this list without approval Input File Format Each instruction is on a separate line, with its operand (if any) on the following line. The instruction or operand may be followed by a comment which the loader will ignore. Anything following an integer is a comment, whether or not it begins with //. A line may be blank in which case the loader will skip it without advancing the load address. A line may begin by a period followed by a number which causes the loader to change the load address. Your program should run correctly with the any valid input files. Sample Programs The input program filename and timer interrupt value should be command line arguments, for example: java Project1 program.txt 30 Here are two sample programs for illustration purposes: This program gets 3 random integers and sums them, then prints the result. Note that each line only has one number. 8 // Get 14 // CopyToX 8 // Get 16 // CopyToY 8 // Get 10 // AddX 11 // Addy 9 / Put 1 1 50 // End This program prints HI followed by a newline to the screen. To demonstrate a procedure call, the newline is printed by calling a procedure. 1 // Load 72=H 72 9 // Put 2 2 1 // Load 73=I 73 9 // Put 2 2 23 / Call 11 11 50 // End 1 // Load 10=newline 10 9 // Put 2 2 24 // Return Language/Platform The project must be written in C, C++, or Java. If using C or C++, you must use a Unix fork to create processes and a Unix pipe for communication. If using Java, you must use the Runtime exec method to create processes and streams for communication. Your project will receive no credit if not using processes or if using threads instead of processes. All code must run successfully on our cs1.utdallas.edu server or csgrads1.utdallas.edu server. Any other method requires instructor approval. Problem Overview The project will simulate a simple computer system consisting of a CPU and Memory. The CPU and Memory will be simulated by separate processes that communicate. Memory will contain one program that the CPU will execute and then the simulation will end. Objectives 1) Learn how multiple processes can communicate and cooperate. 2) Understand low-level concepts important to an operating system. a. Processor interaction with main memory. b. Processor instruction behavior. c. Role of registers. d. Stack processing. e. Procedure calls. Problem Details f. System calls. g. Interrupt handling. h. Memory protection. I/O. 1. j. Virtualization/emulation CPU It will have these registers: PC, SP, IR, AC, X, Y. It will support the instructions shown on the next page of this document. It will run the user program at address 0. Instructions are fetched into the IR from memory. The operand can be fetched into a local variable. Each instruction should be executed before the next instruction is fetched. The user stack resides at the end of user memory and grows down toward address 0. The system stack resides at the end of system memory and grows down toward address 0. There is no hardware enforcement of stack size. The program ends when the End instruction is executed. The 2 processes should end at that time. The user program cannot access system memory (exits with error message). read(address) returns the value at the address write(address, data) - writes the data to the address Memory It will consist of 2000 integer entries, 0-999 for the user program, 1000-1999 for system code. It will support two operations: Memory will initialize itself by reading a program file. Note that the memory is simply storage; it has no real logic beyond reading and writing. Timer A timer will interrupt the processor after every X instructions, where X is a command-line parameter. Interrupt processing There are two forms of interrupts: the timer and a system call using the int instruction. In both cases the CPU should enter kernel mode. The stack pointer should be switched to the system stack. SP and PC registers should be saved on the system stack. (The handler may save additional registers). A timer interrupt should cause execution at address 1000. The int instruction should cause execution at address 1500. The iret instruction returns from an interrupt. Interrupts should be disabled during interrupt processing to avoid nested execution. To make it easy, do not allow interrupts during system calls or vice versa. Instruction set 1 = Load value 2 = Load addr 3 = LoadInd addr 4 = LoadIdxX addr 5 = LoadIdxY addr 6 = LoadSpX 7 = Store addr 8 = Get 9 = Put port 10 = AddX 11 = Addy 12 = SubX 13 = Suby 14 = CopyToX 15 = CopyFromX 16 = CopyToY 17 = CopyFrom Y 18 = CopyToSp 19 = CopyFromSp 20 = Jump addr 21 = JumpIfEqual addr 22 JumpIfNotEqual addr 23 = Call addr 24 = Ret 25 = IncX 26 = DecX 27 Push 28 = Pop 29 = Int 30 IRet 50 End = Load the value into the AC Load the value at the address into the AC Load the value from the address found in the given address into the AC (for example, if LoadInd 500, and 500 contains 100, then load from 100). Load the value at (address+X) into the AC (for example, if LoadIdxX 500, and X contains 10, then load from 510). Load the value at (address+Y) into the AC Load from (Sp+X) into the AC (if SP is 990, and X is 1, load from 991). Store the value in the AC into the address Gets a random int from 1 to 100 into the AC If port=1, writes AC as an int to the screen If port=2, writes AC as a char to the screen Add the value in X to the AC Add the value in Y to the AC Subtract the value in X from the AC Subtract the value in Y from the AC Copy the value in the AC to X Copy the value in X to the AC Copy the value in the AC to Y Copy the value in Y to the AC Copy the value in AC to the SP Copy the value in SP to the AC Jump to the address Jump to the address only if the value in the AC is zero Jump to the address only if the value in the AC is not zero Push return address onto stack, jump to the address Pop return address from the stack, jump to the address Increment the value in X Decrement the value in X Push AC onto stack Pop from stack into AC Perform system call Return from system call End execution Don't add to this list without approval Input File Format Each instruction is on a separate line, with its operand (if any) on the following line. The instruction or operand may be followed by a comment which the loader will ignore. Anything following an integer is a comment, whether or not it begins with //. A line may be blank in which case the loader will skip it without advancing the load address. A line may begin by a period followed by a number which causes the loader to change the load address. Your program should run correctly with the any valid input files. Sample Programs The input program filename and timer interrupt value should be command line arguments, for example: java Project1 program.txt 30 Here are two sample programs for illustration purposes: This program gets 3 random integers and sums them, then prints the result. Note that each line only has one number. 8 // Get 14 // CopyToX 8 // Get 16 // CopyToY 8 // Get 10 // AddX 11 // AddY 9 / Put 1 1 50 // End This program prints HI followed by a newline to the screen. To demonstrate a procedure call, the newline is printed by calling a procedure. 1 // Load 72=H 72 9 // Put 2 2 1 // Load 73=I 73 9 // Put 2 2 23 / Call 11 11 50 // End 1 // Load 10=newline 10 9 // Put 2 2 24 // Return Language/Platform The project must be written in C, C++, or Java. If using C or C++, you must use a Unix fork to create processes and a Unix pipe for communication. If using Java, you must use the Runtime exec method to create processes and streams for communication. Your project will receive no credit if not using processes or if using threads instead of processes. All code must run successfully on our cs 1.utdallas.edu server or csgrads1.utdallas.edu server. Any other method requires instructor approval. Problem Overview The project will simulate a simple computer system consisting of a CPU and Memory. The CPU and Memory will be simulated by separate processes that communicate. Memory will contain one program that the CPU will execute and then the simulation will end. Objectives 1) Learn how multiple processes can communicate and cooperate. 2) Understand low-level concepts important to an operating system. a. Processor interaction with main memory. b. Processor instruction behavior. c. Role of registers. d. Stack processing. e. Procedure calls. Problem Details f. System calls. g. Interrupt handling. h. Memory protection. I/O. 1. j. Virtualization/emulation CPU It will have these registers: PC, SP, IR, AC, X, Y. It will support the instructions shown on the next page of this document. It will run the user program at address 0. Instructions are fetched into the IR from memory. The operand can be fetched into a local variable. Each instruction should be executed before the next instruction is fetched. The user stack resides at the end of user memory and grows down toward address 0. The system stack resides at the end of system memory and grows down toward address 0. There is no hardware enforcement of stack size. The program ends when the End instruction is executed. The 2 processes should end at that time. The user program cannot access system memory (exits with error message). read(address) returns the value at the address write(address, data) - writes the data to the address Memory It will consist of 2000 integer entries, 0-999 for the user program, 1000-1999 for system code. It will support two operations: Memory will initialize itself by reading a program file. Note that the memory is simply storage; it has no real logic beyond reading and writing. Timer A timer will interrupt the processor after every X instructions, where X is a command-line parameter. Interrupt processing There are two forms of interrupts: the timer and a system call using the int instruction. In both cases the CPU should enter kernel mode. The stack pointer should be switched to the system stack. SP and PC registers should be saved on the system stack. (The handler may save additional registers). A timer interrupt should cause execution at address 1000. The int instruction should cause execution at address 1500. The iret instruction returns from an interrupt. Interrupts should be disabled during interrupt processing to avoid nested execution. To make it easy, do not allow interrupts during system calls or vice versa. Instruction set 1 = Load value 2 = Load addr 3 = LoadInd addr 4 = LoadIdxX addr 5 = LoadIdxY addr 6 = LoadSpX 7 = Store addr 8 = Get 9 = Put port 10 = AddX 11 = Addy 12 = SubX 13 = Suby 14 = CopyToX 15 = CopyFromX 16 = CopyToY 17 = CopyFrom Y 18 = CopyToSp 19 = CopyFromSp 20 = Jump addr 21 = JumpIfEqual addr 22 = JumpIfNotEqual addr 23 = Call addr 24 = Ret 25 = IncX 26 = DecX 27 Push 28 = Pop 29 = Int 30 IRet 50 End = Load the value into the AC Load the value at the address into the AC Load the value from the address found in the given address into the AC (for example, if LoadInd 500, and 500 contains 100, then load from 100). Load the value at (address+X) into the AC (for example, if LoadIdxX 500, and X contains 10, then load from 510). Load the value at (address+Y) into the AC Load from (Sp+X) into the AC (if SP is 990, and X is 1, load from 991). Store the value in the AC into the address Gets a random int from 1 to 100 into the AC If port=1, writes AC as an int to the screen If port=2, writes AC as a char to the screen Add the value in X to the AC Add the value in Y to the AC Subtract the value in X from the AC Subtract the value in Y from the AC Copy the value in the AC to X Copy the value in X to the AC Copy the value in the AC to Y Copy the value in Y to the AC Copy the value in AC to the SP Copy the value in SP to the AC Jump to the address Jump to the address only if the value in the AC is zero Jump to the address only if the value in the AC is not zero Push return address onto stack, jump to the address Pop return address from the stack, jump to the address Increment the value in X Decrement the value in X Push AC onto stack Pop from stack into AC Perform system call Return from system call End execution Don't add to this list without approval Input File Format Each instruction is on a separate line, with its operand (if any) on the following line. The instruction or operand may be followed by a comment which the loader will ignore. Anything following an integer is a comment, whether or not it begins with //. A line may be blank in which case the loader will skip it without advancing the load address. A line may begin by a period followed by a number which causes the loader to change the load address. Your program should run correctly with the any valid input files. Sample Programs The input program filename and timer interrupt value should be command line arguments, for example: java Project1 program.txt 30 Here are two sample programs for illustration purposes: This program gets 3 random integers and sums them, then prints the result. Note that each line only has one number. 8 // Get 14 // CopyToX 8 // Get 16 // CopyToY 8 // Get 10 // AddX 11 // Addy 9 / Put 1 1 50 // End This program prints HI followed by a newline to the screen. To demonstrate a procedure call, the newline is printed by calling a procedure. 1 // Load 72=H 72 9 // Put 2 2 1 // Load 73=I 73 9 // Put 2 2 23 / Call 11 11 50 // End 1 // Load 10=newline 10 9 // Put 2 2 24 // Return

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Cpujava import javaio import javautilRandom import javautilScanner public class CPU Declare required registers static int PC 0 SP 1000 IR AC X Y timerFlag numofinstructions 0 static int systemStacktop ... View the full answer