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b. Consider the language L={w/w contains at least three Is} over the alphabet ? = {0,1}. Let R be the regular expression that generates the language L. The regular expression is as follows: R = * 1 *1*1 * = (0+1)*1(0+1)*1(0+1)*1(0+1)* The strings accepted by the regular expression are 111,010101,01101,00001111,... Therefore, the regular expression is (0+1) * 1(0+1)*1(0+1)*1(0+1)* . e. Consider the language, L={w w starts with O and has odd length, or start with 1 and has even length over the alphabet = {0,1}. Let R be the regular expression that generates the language L. The regular expression is as follows: R = 0()* +()* = 0(0+1)(0+1))* +1(0+1)(0+1)(0+1))* The strings accepted by the regular expression are 0,011,010,00101,10,11,1001,... Therefore, the regular expression is 0((0+1)(0+1))* +1(0+1)((0+1)(0+1))*