oders of masses m, = 100 kg and m, = 50 kg ered by a rigid...

 

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oders of masses m, = 100 kg and m, = 50 kg ered by a rigid bar of negligible weight hinged at each 2) Its average velocity during the interval 6 <t< 14 sec. shown in Fig. Ex. 3.8.17 knowing that x =0 and v = 60 m/s when The acceleration for a small plane travelling along a straight line is t= 0. Determine D The velocity and position of plane at t = 20 sec. a 2 0.75m/s nlo2 6. 8 10 +t(sec) 20 0. 12 14 0.75m/s Fig. Ex. 3.8.17 gineeniny nd Equilibrium Fcos 15-Rcos 45-Pcon 45s-0 P. 1641.24 -R R sin 45-Psin AS-905-1201AT sn 19 0 ..1) 45 .R sin 45-P sin 45 01.46 15 Divide by sin 45 .R, - P+1133 435 in Equation (1) 1641 24-(P+1133.435) Fig. Ex. 11.10.20o P2539N An. e FB.D. of two cylinders de the compressive force in rigid bar AB. br use Lami's theorem for cylinder A. A thin Tig of mass 3 kg and radius 140 mm is held apinta frictionless wall by a string of length 120 mm. Find distance dnd tension in the string 981 sin 135 = sin 120° R, = 1340.07 N = 1201.47 N (compressive) 120mm R1 135° 15°.. l0g 30° 120 140mmm *.. 981N B.D. Tis E 11 10 20(n) oders of masses m, = 100 kg and m, = 50 kg ered by a rigid bar of negligible weight hinged at each 2) Its average velocity during the interval 6 <t< 14 sec. shown in Fig. Ex. 3.8.17 knowing that x =0 and v = 60 m/s when The acceleration for a small plane travelling along a straight line is t= 0. Determine D The velocity and position of plane at t = 20 sec. a 2 0.75m/s nlo2 6. 8 10 +t(sec) 20 0. 12 14 0.75m/s Fig. Ex. 3.8.17 gineeniny nd Equilibrium Fcos 15-Rcos 45-Pcon 45s-0 P. 1641.24 -R R sin 45-Psin AS-905-1201AT sn 19 0 ..1) 45 .R sin 45-P sin 45 01.46 15 Divide by sin 45 .R, - P+1133 435 in Equation (1) 1641 24-(P+1133.435) Fig. Ex. 11.10.20o P2539N An. e FB.D. of two cylinders de the compressive force in rigid bar AB. br use Lami's theorem for cylinder A. A thin Tig of mass 3 kg and radius 140 mm is held apinta frictionless wall by a string of length 120 mm. Find distance dnd tension in the string 981 sin 135 = sin 120° R, = 1340.07 N = 1201.47 N (compressive) 120mm R1 135° 15°.. l0g 30° 120 140mmm *.. 981N B.D. Tis E 11 10 20(n)