Question: Leap Year Function First, write a function is _ leap _ year which returns a boolean ( either True or False ) depending on whether

Leap Year Function
First, write a function is_leap_year which returns a boolean (either True or False) depending on whether the year should be a leap year.
Our current definition of a leap year is as follows:
Years divisible by 4 are leap years, unless the year is also divisible by 100. Years divisible by 4 and 100 are leap years only if they are also divisible by 400.
So for example:
2023 is not a leap year because it is not divisible by 4.
1992 is divisible by 4, but it is not divisible by 100, so it is a leap year.
1900 is divisible by 4, and divisible by 100. Since it is not also divisible by 400, it is not a leap year.
2000 is divisible by 4 and by 100. However, it is also divisible by 400, so 2000 is a leap year.
One approach might be to think of some decisions:
Is the year divisible by 4?
No: Not a leap year.
Yes: Then is the year divisible by 100?
No: The year is a leap year.
Yes: Then is it also divisible by 400?
Yes: The year is a leap year.
No: The year is not a leap year.
Your function will either require some if/else (or elif) statements, or you will need an expression using boolean operators. Either approach is fine.
Write the is_leap year function which takes a single whole number and returns whether or not the year should be a leap year:
Leap Year Function First, write a function is _

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