Learning Goal:

At what temperature is the root$-$mean$-$square speed of nitrogen molecules equal to the root$-$mean$-$square speed of hydrogen molecules at $20\mathrm{.}0$C$$C$?$

The molar mass of a nitrogen atom is $14\mathrm{.}0$ g$/$molg$/$mol and the molar mass of a hydrogen atom is $1\mathrm{.}01$ g$/$molg$/$mol$.$

At what temperature TN$2$TN$2$ is the root$-$mean$-$square speed of nitrogen molecules equal to the root$-$mean$-$square speed of hydrogen molecules at $20\mathrm{.}0$C$$C$?$

Part C

If nitrogen and hydrogen molecules are at the same temperature, how do their root$-$mean$-$square speeds compare?

View Available Hint$($s$)$for Part C

vrmsvrms of N$2$N$2$ is lower than vrmsvrms of H$2$H$2.$vrmsvrms of N$2$N$2$ is higher than vrmsvrms of H$2$H$2.$vrmsvrms of N$2$N$2$ is equal to vrmsvrms of H$2$H$2.$