lecture $11.$pdf

File

C:$/$Users$/$mkhan$7/$Documents$/$Design$/$lecture$\%2011.$pdf

Draw

$30$

of $44$

$00mm$;$N_1=360$ r$.$p$.$m$.$ ;$N_2=120$ r$.$p$.$m$.$ ;$p_c=25mm$

$\frac{N_1}{N_2}=\frac{d_2}{d_1}=\frac{360}{120}=3or{d}_2=3d_1$

$00=\frac{1}{2}(d_1+d_2)or{d}_1+d_2=1200$

$r_1+r_2=600mm$

$\frac{D_1}{2}+\frac{D_2}{2}=600mm$

$\frac{N_1}{N_2}=\frac{T_2}{N_1}=\frac{D_2}{D_1}$

$\frac{360}{120}=\frac{D_2}{D_1}$

$D_1=\frac{D_{1}120}{360}$

$d_1=300mm$ and $d_2=900mm$

Problem

Given : $x=600mm$;$N_1=360$ r$.$p$.$m$.$ ;$N_2=120$ r$.$p$.$m$.$ ;$p_c=25mm$

$p_c=\frac{D}{T}$

arouen