Question: Lecture: Decidability 2 . Let A epsi CFG = { G | G is a CFG that generates epsi } . Show that

Lecture: Decidability
2. Let A\epsi CFG ={G| G is a CFG that generates \epsi }. Show that A\epsi CFG is decidable. (20 points)
(Hints: Create a Turing machine M, For each xL, M either accepts or rejects x)
Answer:
Lecture: Decidability
3. In the chapter of regular language, we know that the DFA is equivalent with NFA and regular expression (RE). For the problem to determine whether a given DFA and RE are the same, C ={| D is a DFA and R is a RE that L(D)= L (R)}, please prove that C is decidable. (20 points)
(Hints: Create a Turing machine M, For each xL, M either accepts or rejects x)
Answer:
Lecture: Reducibility
4. Show that EQ CFG is undecidable. (20 points)
Hint: You can directly use the result of Theorem 5.13. That is, instead of considering a reduction from ATM, you can directly consider a reduction from ALLCFG.
Lecture: Complexity
5. Answer each part TRUE or FALSE. (20 points)
a.2n = O(n).
b. n2= O(n).
c.3n =2O(n).
d.22n = O(22n ).
Please also justify each of your true/false answers using the Definition 7.2.
In more details: what is f(n), what is g(n), whether c and n0 exist so that when n>=n0 that inequation is always true.

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