Left Hand Rule and Ampere's Law Practice Problems

I need assistance with the direction of the field on the following (I solved the problems but I haven't quite understand yet how the direction of the field goes.

1. A wire has a current (I) of 0.500 A traveling through it. What is the strength of the magnetic (B)field a distance(d) of 0.010 m away from the wire? Also, use the diagram to indicate the direction of the field. - See attached Image A

Solution:

B=kI/d=(2.00 x 10^-7) x 0.5 / 0.010 = 1/100000=0.00001=1 x 10^-5 T.m/A

2. A wire has a current (I)of 0.100 A traveling through it. What is the strength of the magnetic field (B)a distance (d)of 0.003 m away from the wire? Also, use the diagram to indicate the direction of the current from the direction of the field.

Solution:

B=kI/d=(2.00 x 10^-7) x 0.1 / 0.003 = 1/150000=6.667 x 10^-6 T.m/A - See attached image B

3. A wire with a current traveling through it is found to have a magnetic field of strength(B) 0.005 T at a distance (d)of 0.002 m from the wire. What is the current (I)that is traveling through this wire? Also, indicate the direction of the field from the diagram below. - See attached Image C

Solution:

0.005=(2.00 x 10^-7) x I /0.002

I=0.005 x 0.002 / (2.00 x 10^-7)=50 A

4. Look at the image of the solenoid that appears below. Use the second left hand rule to determine the direction of the field created by the solenoid and to label the ends north and south. - See attached image D