Let $A[1$:$n]$ be a min$-$heap, where $n>1$ and $n$ is even. Then $A[\frac{n}{2}+1$:$n]$

is always a min$-$heap.

Note that the notation $A[i$:$j]$ represents the array$/$subarray A between the

indexes i and $j.$

True

False

Default