Question: Let A and B be mutually exclusive events, such that P(A) = 0.4752 and P(B) = 0.3257. Find the following probabilities: P(A and B)=

Let A and B be mutually exclusive events, such that P(A) =

Let A and B be mutually exclusive events, such that P(A) = 0.4752 and P(B) = 0.3257. Find the following probabilities: P(A and B)= 0 % (Round the answer to 2 decimals) P(A or B)= 65.7 X% (Round the answer to 2 decimals)

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